GreenFET3 SLG59M1606V - dual power supply switch schematic recommendation
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I'm confused, "unfortunately reverse current blocking works only when device is off, so you will need to switch power rail manually" - can you explain it? I've sent a schematic block diagram with two pwr switches. I expected it's doable like it's illustrated in AN-1096 Fig. 1A
SLG59M1606 has reverse current blocking when device is off, that means that if you turn ON one power rail, lets say 4.3V and then apply 5V to VOUT, so this 5V will pass to input of 4.3V power rail, however if you set ON to low, then reverse current will not pass from VOUT to VIN. In case of using SLG59M1639, so besides reverse current blocking, this device has additionally reverse voltage detection, that means that if you apply voltage to VOUT that is higher by at least 50mV than VIN, so device will automatically detect it and shutdown, so you don't need to set ON to low manually. As a conclusion, your application is duable in case of using SLG59M1639 and SLG59M1748 as I described in a previous response. If you will switch 4.3V and 5V power rails manually and the behavior brake before make is ok, so you can use SLG59M1606V as well. Please let me know if you have any questions.
Can we use SLG59M1649 in that case instead of SLG59M1639?
This part of datasheet is unclear for us:
"When enabled, internal reverse-current protection will quickly open the switch in the event of a reverse-voltage condition is detected (a VOUT + 50 mV > VIN condition opens the switch)."
regarding the DS statement, so yes, when VOUT is > than VIN by 50mV, then 1639 will shutdown but to detect this voltage, there should be enough current on VIN side. When you have 4.3V on VIN and apply 5V to VOUT, so this 5V will pass to VIN. The RDS(ON) of 1639 when its VIN1, VIN2 and VOUT1, VOUT2 are paralleled will be around 23mohm, so to generate 50mV difference between VIN and VOUT, you will need to have around 2A current consumption on VIN side. In AN you can see that we use resistor on VIN side for this condition. Based on you schematic it will mean, you need to continuously burn 2A current directly on the output of your DC/DC if you don't use this power rail for any other blocks that may totally consume 2A (please see attached image for better understanding).
Yes, you need to control EN signal if you will always have 5V on VIN and just need to switch between 5V or 4.3V, otherwise you will always have 5V on common VOUT. If you plan that this 5V will be completely disconnected from USB and it it needs to be turned on once USB is connected, so you can set EN high all the time.
For secon load switch it may not work because you described that input should accept 4.3V only and in case you will have 5V there 1639 will automatically switch to that power rail, that is not good for you. You will probably need to check which voltage is present and if it is 5V, then manually turn off that load switch. Or you will need to have some Overvoltage protection. BTW: What is the reason of second power switch if your IC charger supports both 4.3V and 5V, and anyway you make 4.3V at the end?
Hi Bartosz. Thank you for interesting in our prodcuts. Can you please give me some information regarding your application:
1.两个电源轨的输入电压是多少?
2. Do you need automatic turn off when reverse voltage is detected?
3.最大开关电流是多少?
Hi,
1. First: 4.3V @ 3A, Second: 5V @ 1A
2.是(第一个是主电源)
3. As above.
Hi Bartosz,
谢谢你的回复。电压水平和电流是可以接受的这个SLG59M1606,但不幸的是反向电流阻断工程只有当设备是关闭的,所以你需要切换电源轨手动。对于您的应用,我们建议您使用双通道SLG59M1639用于4.3V@3A,SLG59M1748用于5V@1A。请参阅随附的示意图以供参考。使用此负载开关1639将自动检测5V的反向电压。我还建议您阅读这篇文章,了解如何在像您这样的应用程序中使用LS亚博国际官网平台网址//www.xmece.com/AN-1096. 如果你有任何问题,请告诉我。
Hi,
I'm confused, "unfortunately reverse current blocking works only when device is off, so you will need to switch power rail manually" - can you explain it? I've sent a schematic block diagram with two pwr switches. I expected it's doable like it's illustrated in AN-1096 Fig. 1A
当做,
巴尔托什
Hi Bartosz,
SLG59M1606 has reverse current blocking when device is off, that means that if you turn ON one power rail, lets say 4.3V and then apply 5V to VOUT, so this 5V will pass to input of 4.3V power rail, however if you set ON to low, then reverse current will not pass from VOUT to VIN. In case of using SLG59M1639, so besides reverse current blocking, this device has additionally reverse voltage detection, that means that if you apply voltage to VOUT that is higher by at least 50mV than VIN, so device will automatically detect it and shutdown, so you don't need to set ON to low manually. As a conclusion, your application is duable in case of using SLG59M1639 and SLG59M1748 as I described in a previous response. If you will switch 4.3V and 5V power rails manually and the behavior brake before make is ok, so you can use SLG59M1606V as well. Please let me know if you have any questions.
Hi
为了确保,在使用SLG59M1639和SLG59M1748的情况下,如您在上一条消息中所述,保持SLG59M1639的EN pin高和SLG59M1748 EN pins低,将允许我创建自动工作的开关,不是吗?静态电流呢?
当做,
巴尔托什
嗨,巴托斯。是的,您只需在SLG59M1748中切换EN即可在5V或4.3V之间自动切换,但请确保您满足我之前发给您的一封信中描述的1639反向电压检测要求(我的意思是1639的VIN侧应有足够的电流来检测反向电压)。关于静态电流,所以一旦1639关闭它将消耗相同的电流时,因为它是开信号将仍然很高。如果你有任何问题,请告诉我。
嗨,佩特罗,
Can we use SLG59M1649 in that case instead of SLG59M1639?
This part of datasheet is unclear for us:
"When enabled, internal reverse-current protection will quickly open the switch in the event of a reverse-voltage condition is detected (a VOUT + 50 mV > VIN condition opens the switch)."
“我的意思是1639的VIN侧应该有足够的电流来检测反向电压”-将连接60V蓄电池,您所说的VIN上的足够电流是什么意思?
So, I need to control EN signal of SLG59M1748C, don't I? or just connect to logic high all time.
第二个开关,我已经在电源块草案开始-可以取代两个SLG59M1639和开关自动?
Hi Bartosz.
SLG59M1649在关闭时有内部放电(但只有在通过启用引脚关闭时),因此如果这对您来说不是问题,那么您也可以使用它。
regarding the DS statement, so yes, when VOUT is > than VIN by 50mV, then 1639 will shutdown but to detect this voltage, there should be enough current on VIN side. When you have 4.3V on VIN and apply 5V to VOUT, so this 5V will pass to VIN. The RDS(ON) of 1639 when its VIN1, VIN2 and VOUT1, VOUT2 are paralleled will be around 23mohm, so to generate 50mV difference between VIN and VOUT, you will need to have around 2A current consumption on VIN side. In AN you can see that we use resistor on VIN side for this condition. Based on you schematic it will mean, you need to continuously burn 2A current directly on the output of your DC/DC if you don't use this power rail for any other blocks that may totally consume 2A (please see attached image for better understanding).
Yes, you need to control EN signal if you will always have 5V on VIN and just need to switch between 5V or 4.3V, otherwise you will always have 5V on common VOUT. If you plan that this 5V will be completely disconnected from USB and it it needs to be turned on once USB is connected, so you can set EN high all the time.
For secon load switch it may not work because you described that input should accept 4.3V only and in case you will have 5V there 1639 will automatically switch to that power rail, that is not good for you. You will probably need to check which voltage is present and if it is 5V, then manually turn off that load switch. Or you will need to have some Overvoltage protection. BTW: What is the reason of second power switch if your IC charger supports both 4.3V and 5V, and anyway you make 4.3V at the end?
Please let me know if you have any questions.
我们能打个电话吗(hangouts/zoom/teams)?
My email isbziolek@taoglas.com
当做,
巴尔托什
当然,我只是在闲逛的时候给你写信。
Hi,
SLG59M1649V的针脚ON处于高电平或低电平激活状态?我认为方框图中的数据表(1.01)有错误。应为SW关闭->SW打开。描述正确:“此引脚上的低到高转换启动电源开关的操作。ON是一个高电平敏感CMOS输入,ON VIL<0.3 V,ON VIH>1 V。由于ON输入电路没有内部下拉电阻器,请将ON引脚直接连接到GPIO控制器–不要使该引脚开路。“您能确认吗?
当做,
巴尔托什
Hi Bartosz.
它是高电平,方框图中的描述是正确的。当我们谈论负载开关,MOSFET以及一般的触点时,闭合意味着打开,打开意味着关闭。https://thegrid.rexel.com/en-us/knowledge/product-faqs/w/wiki/928/contac....