Configuring BLE with UART

Hello there,

I'm trying to use UART in parallel with BLE. For the purpose of my project, Codeless and DSPS were not applicable and making adequate modifications was impossible. Therefore, I decided to use the UART functionalities demonstrated in example project in conjuction with ble_app_peripheral example.

That being said, After importing some of the libraries which were required and enabling dma mode in ble example; I followed this proccess:

• Upon subscription to adc value 1, I want to start reading the data every 5 seconds.

空白user_svc1_adc_val_1_cfg_ind_handler (ke_msg_id_t const msgid, struct custs1_val_write_ind const *param, ke_task_id_t const dest_id, ke_task_id_t const src_id) { // Generate indication when the central subscribes to it if (param->value[0]){ printf_string(UART2,"The user has subscribed to ADC characteristic!\n\r"); SendRecSM_op(); } }

• 我尝试使用不同的中断模式：

ke_msg_id_t timer_used_sendrec_sm __section_zero（“保留_mem_area0”）;// @保留内存UART_T * UART = UART2;const int read_char_count = 5;静态char buffer_ble [read_char_count + 1];volatile bool uart_receive_finished = false;volatile uint16_t data_received_cnt = 0;//函数定义void sendrecsm_op（）{// blocking_receive_uart（）;intr_receive_uart（）;// dma_receive_uart（）;app_easy_timer（500，UART_CHK_BUFFER_CB）; } static void uart_receive_cb(uint16_t length){ data_received_cnt = length; uart_receive_finished = true; } void dma_receive_uart(){ uart_receive_finished = false; data_received_cnt = 0; uart_register_rx_cb(uart, uart_receive_cb); //Time to ask for data! uart_receive(uart, (uint8_t *)buffer_BLE, READ_CHAR_COUNT, UART_OP_DMA); } void uart_chk_buffer_cb() { arch_printf("\n\rChecking the buffer!\n\r"); if (uart_receive_finished){ buffer_BLE[READ_CHAR_COUNT] = 0; // make it a null terminated string printf_string(uart,buffer_BLE); } } void intr_receive_uart(){ uart_receive_finished = false; data_received_cnt = 0; uart_register_rx_cb(uart, uart_receive_cb); //Time to ask for data! arch_printf("UART is in Interrupt mode!\n\r"); arch_printf("Please input the data!"); uart_receive(uart, (uint8_t *)buffer_BLE, READ_CHAR_COUNT, UART_OP_INTR); } void blocking_receive_uart(){ printf_string(uart,"UART is in Blocking mode!\n\r"); printf_string(uart,"Please input the data!"); uart_receive(uart, (uint8_t *)buffer_BLE, READ_CHAR_COUNT, UART_OP_BLOCKING); buffer_BLE[READ_CHAR_COUNT] = 0; // make it a null terminated string printf_string(uart,buffer_BLE); }

In case of blocking recieve, I'm not using the timer. However, If I don't input the data right away, the program crashes due to"while (!uart_data_ready_getf(uart_id));"command in"uart_read_byte()".

如果中断接收，我使用所述计时器。但是，该程序仅运行一次。换句话说，它只打印"Checking the buffer!"无论我会做什么，一切都会冻结。

• If I stick to the original code and use"while(!receive_uart_finished);"the programm will crash due to the same line of code.

I wanted to know, what can I do to solve these problems? Is there a something that I haven't configured for the UART? Is there a better way to do this? (except for using codeless or dsps, because they seem extremely hard to modify)